CST MWS球型螺旋天線怎么畫(huà)啊
球型螺旋天線怎么畫(huà)啊 ??高手指導(dǎo)一下 !多謝!
頂個(gè)
我也想知道
沒(méi)做過(guò)天線,能把模型和尺寸發(fā)上來(lái)嗎?這樣知道的人會(huì)比較多
郁悶.高手都在春眠嗎
到這個(gè)地方看看吧 應(yīng)該對(duì)你有幫助
http://www.mwhrf.com/dispbbs.asp?BoardID=2&ID=2392&replyID=&skin=1
請(qǐng)到 http://imw.mwhrf.com/thread-10719-1-1.html
看看!
在CST-->Macros--->construct---->curves---->creat 3D curves analytical(xyz-wcs)-------------------------- >出現(xiàn)一個(gè)螺旋線-------->到history把VBA code改成下述.
CST VBA code
------------------------------------------------------------------------------------------------------------------------------------
On Error GoTo Curve_Exists
Curve.NewCurve "3D-Analytical"
Curve_Exists:
On Error GoTo 0
Dim sCurveName As String
sCurveName = "3dpolygon_1"
With Polygon3D
.Reset
.Name sCurveName
.Curve "3D-Analytical"
' ======================================
' !!! Do not change ABOVE this line !!!
' ======================================
' -----------------------------------------------------------
' adjust x-range as for-loop parameters (xmin,max,step)
' enter y/z-Function-statement within for-loop
' fixed parameters a,b,c have to be declared via Dim-Statement
' -----------------------------------------------------------
' NOTE: available MWS-Parameters can be used without
' declaration at any place (loop-dimensions, ...)
' (for parametric curves during parameter-sweeps and optimisation !)
' -------------------------------------------
Dim x As Double, y As Double, z As Double
Dim rho As Double, theta As Double, phi As Double
Dim t As Double
For t=-0.25*Pi To 0.25*Pi STEP 0.001 ( 此設(shè)定剛好繞球一圈)
rho=10 (sphere radius)
theta=t
phi=2*t
x=rho*( sin(theta*100) )*cos(phi) (*100, 控制螺旋圈數(shù))
y=rho*( cos(theta*100) )*cos(phi)
z=-rho*sin(phi)
.Point x, y, z
Next t
' ======================================
' !!! Do not change BELOW this line !!!
' ======================================
.Create
End With
SelectTreeItem("Curves3D-Analytical"+sCurveName)
Re:球型螺旋天線怎么畫(huà)啊
路過(guò),贊mfhsu
能不能給出個(gè)sat格式的模型,讓大家都瞅瞅。或者直接CST模型也行啊
您好,這個(gè)是cst建的模吧,怎么畫(huà)呢?尤其是每根的粗細(xì)